Make sure mass is in GRAMS before dividing by Mr. If given mass in kg, multiply by 1000 first. Also: 1 mole of H₂O contains 6.02 × 10²³ MOLECULES — but 3 × 6.02 × 10²³ ATOMS (2 H + 1 O per molecule). Always be clear about what particles are being counted.
📐 Variables
nAmount in moles (n) is measured in mol (mol)
mMass (m) is measured in grams (g)
MrRelative formula mass (Mr) is measured in ()
NₐAvogadro constant (Nₐ) is measured in mol⁻¹ (6.02 × 10²³)
📐 Key Equations
moles (mol) = mass (g) ÷ Mr
mass (g) = moles (mol) × Mr
number of particles = moles × 6.02 × 10²³
% mass = (Ar × number of atoms ÷ Mr) × 100
📌 Key Note
1 mole = 6.02 × 10²³ particles (Avogadro constant). n = m ÷ Mr. The molar mass = Mr in g/mol. % mass = (Ar × atoms ÷ Mr) × 100.
🎯 Matching Activity — Moles Calculations
Match each calculation to the correct answer. — drag the symbols on the right to match the component names on the left.
Moles in 40 g NaOH (Mr=40)
Drop here
Mass of 2 mol CO₂ (Mr=44)
Drop here
Moles in 5.6 g Fe (Ar=56)
Drop here
Particles in 0.5 mol
Drop here
% mass of Ca in CaCO₃ (Mr=100)
Drop here
3.01 × 10²³ — 0.5 × 6.02 × 10²³
40% — (40 ÷ 100) × 100 = 40%
0.1 mol — n = 5.6 ÷ 56 = 0.1
88 g — mass = 2 × 44 = 88
1 mol — n = 40 ÷ 40 = 1
⚽ FIFA Worked Examples
Moles from Mass
Calculate the number of moles in 27 g of aluminium (Ar = 27).
F
moles = mass ÷ Mr
I
moles = 27 ÷ 27
F
moles = 1
A
1 mol of aluminium
🎯 Test Yourself
Question 1 of 2
1. How many moles are in 9.8 g of sulfuric acid (H₂SO₄)? Mr = 98.
2. What mass of calcium carbonate (CaCO₃, Mr = 100) contains 3.01 × 10²³ formula units?
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