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πŸ§ͺ Relative Formula Mass

Spec 5.3.1.2 πŸ“™ Higher
πŸ“– In-Depth Theory

Relative Formula Mass (Mr)

The RELATIVE FORMULA MASS (Mr) of a compound is the sum of the RELATIVE ATOMIC MASSES (Ar) of all atoms in its formula.
Mr has no units β€” it is a ratio (relative to carbon-12).
You need the Ar values from the periodic table:
H = 1, C = 12, N = 14, O = 16, Na = 23, Mg = 24, S = 32, Cl = 35.5, Ca = 40, Fe = 56
EXAMPLES:
Hβ‚‚O: (2 Γ— 1) + (1 Γ— 16) = 2 + 16 = 18
COβ‚‚: (1 Γ— 12) + (2 Γ— 16) = 12 + 32 = 44
NaCl: (1 Γ— 23) + (1 Γ— 35.5) = 23 + 35.5 = 58.5
MgO: (1 Γ— 24) + (1 Γ— 16) = 24 + 16 = 40
Hβ‚‚SOβ‚„: (2 Γ— 1) + (1 Γ— 32) + (4 Γ— 16) = 2 + 32 + 64 = 98
CaCO₃: (1 Γ— 40) + (1 Γ— 12) + (3 Γ— 16) = 40 + 12 + 48 = 100

Mr for Ionic Compounds with Brackets

When a formula contains BRACKETS, multiply everything inside the brackets by the number outside.
Examples:
Ca(OH)β‚‚:
Ca: 40
O: 16 Γ— 2 = 32 (there are 2 OH groups, each with 1 O)
H: 1 Γ— 2 = 2 (each OH group has 1 H, Γ— 2 groups)
Mr = 40 + 32 + 2 = 74
Mg(NO₃)β‚‚:
Mg: 24
N: 14 Γ— 2 = 28
O: 16 Γ— 6 = 96 (each NO₃ has 3 O, Γ— 2 groups)
Mr = 24 + 28 + 96 = 148
Alβ‚‚(SOβ‚„)₃:
Al: 27 Γ— 2 = 54
S: 32 Γ— 3 = 96
O: 16 Γ— 12 = 192 (each SOβ‚„ has 4 O, Γ— 3 groups)
Mr = 54 + 96 + 192 = 342

Using Mr in Mass Calculations

Mr allows us to calculate MASSES in reactions from a balanced equation.
FUNDAMENTAL PRINCIPLE:
The RATIO of masses of reactants and products in a reaction equals the RATIO of their Mr values (multiplied by the coefficients in the balanced equation).
Example:
2Mg + Oβ‚‚ β†’ 2MgO
Mr: Mg = 24, Oβ‚‚ = 32, MgO = 40
Ratio of masses: 2 Γ— 24 : 32 : 2 Γ— 40 = 48 : 32 : 80
So: 48 g of Mg reacts with 32 g of Oβ‚‚ to produce 80 g of MgO.
OR: to find mass of MgO from 12 g of Mg:
Scale factor = 12 Γ· 48 = 0.25
Mass of MgO = 80 Γ— 0.25 = 20 g
This is the foundation for all quantitative chemistry calculations.
⚠️ Common Mistake

When a formula has BRACKETS with a subscript, MULTIPLY all atoms inside the bracket by the subscript. Ca(OH)β‚‚ has 2 oxygen atoms and 2 hydrogen atoms β€” not 1 of each. Write out the count carefully: Ca(OH)β‚‚ = Ca + 2O + 2H = 40 + 32 + 2 = 74.

πŸ“ Variables
MrRelative formula mass (Mr) is measured in ()
ArRelative atomic mass (Ar) is measured in ()
πŸ“ Key Equations
Mr = sum of all Ar values in the formula
πŸ“Œ Key Note

Mr = sum of all Ar values in the formula. Use Ar from periodic table. Brackets: multiply atoms inside by the subscript outside. Mr is used to calculate mass ratios in reactions. Mr has no units.

🎯 Matching Activity β€” Calculate the Mr

Match each formula to its correct relative formula mass. β€” drag the symbols on the right to match the component names on the left.

Hβ‚‚O
Drop here
COβ‚‚
Drop here
NaCl
Drop here
CaCO₃
Drop here
Ca(OH)β‚‚
Drop here
Mr = 58.5 β€” (1 Γ— 23) + (1 Γ— 35.5)
Mr = 74 β€” (1 Γ— 40) + (2 Γ— 16) + (2 Γ— 1)
Mr = 44 β€” (1 Γ— 12) + (2 Γ— 16)
Mr = 18 β€” (2 Γ— 1) + (1 Γ— 16)
Mr = 100 β€” (1 Γ— 40) + (1 Γ— 12) + (3 Γ— 16)
⚽ FIFA Worked Examples
Mr Calculation β€” Hβ‚‚SOβ‚„

Calculate the relative formula mass of sulfuric acid (Hβ‚‚SOβ‚„). Ar: H=1, S=32, O=16.

F

Mr = sum of all Ar values Γ— number of atoms

I

H: 1 Γ— 2 = 2. S: 32 Γ— 1 = 32. O: 16 Γ— 4 = 64

F

Mr = 2 + 32 + 64

A

Mr = 98

⭐ Higher Tier Only

Calculate percentage mass of an element in a compound: (Ar Γ— number of atoms Γ· Mr) Γ— 100. Calculate empirical formula from percentage composition. Convert empirical to molecular formula using Mr. These skills are foundations for mole calculations.

🎯 Test Yourself
Question 1 of 2
1. What is the relative formula mass of calcium carbonate (CaCO₃)? Ar: Ca=40, C=12, O=16.
2. What is the Mr of Mg(NO₃)β‚‚? Ar: Mg=24, N=14, O=16.
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