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๐Ÿงช Effect of Changing Conditions on Equilibrium

Spec 5.6.2.4โ€“5.6.2.7 ๐Ÿ“™ Higher
๐Ÿ“– In-Depth Theory

Le Chatelier's Principle

LE CHATELIER'S PRINCIPLE states:
If a system at equilibrium is disturbed by a change in conditions, the equilibrium will SHIFT in the direction that OPPOSES the change.
This is a prediction tool โ€” it allows chemists to predict the effect of changes WITHOUT knowing the detailed kinetics.
Types of changes:
1. Changing CONCENTRATION of a reactant or product.
2. Changing TEMPERATURE.
3. Changing PRESSURE (for gaseous reactions).
The system responds by shifting the equilibrium position LEFT (โ†’ more reactants) or RIGHT (โ†’ more products).
Note: a catalyst DOES NOT shift the equilibrium position โ€” it speeds up BOTH forward and reverse reactions equally, so equilibrium is reached FASTER but the position is unchanged.

Effect of Concentration and Pressure

CHANGING CONCENTRATION:
INCREASE concentration of REACTANT โ†’ equilibrium shifts RIGHT (โ†’ uses up added reactant, making more product).
INCREASE concentration of PRODUCT โ†’ equilibrium shifts LEFT (โ† uses up added product, making more reactant).
REMOVE a product โ†’ equilibrium shifts RIGHT to replace it.
Example: Nโ‚‚ + 3Hโ‚‚ โ‡Œ 2NHโ‚ƒ
Add more Nโ‚‚ โ†’ equilibrium shifts right โ†’ more NHโ‚ƒ produced.
Remove NHโ‚ƒ โ†’ equilibrium shifts right โ†’ more NHโ‚ƒ produced.
CHANGING PRESSURE (for gaseous reactions):
INCREASE pressure โ†’ equilibrium shifts towards FEWER moles of gas (to reduce pressure).
DECREASE pressure โ†’ equilibrium shifts towards MORE moles of gas (to increase pressure).
Example: Nโ‚‚ + 3Hโ‚‚ โ‡Œ 2NHโ‚ƒ
Left side: 1 + 3 = 4 moles of gas. Right side: 2 moles of gas.
INCREASE pressure โ†’ shifts RIGHT (2 moles) โ†’ more NHโ‚ƒ.
DECREASE pressure โ†’ shifts LEFT (4 moles) โ†’ less NHโ‚ƒ.

Effect of Temperature

CHANGING TEMPERATURE:
INCREASE temperature โ†’ equilibrium shifts in the ENDOTHERMIC direction.
DECREASE temperature โ†’ equilibrium shifts in the EXOTHERMIC direction.
Why: the system absorbs the added heat energy by shifting in the endothermic direction, opposing the temperature increase.
Example: Nโ‚‚ + 3Hโ‚‚ โ‡Œ 2NHโ‚ƒ ฮ”H = โˆ’92 kJ/mol (forward reaction exothermic)
INCREASE temperature โ†’ shifts LEFT (endothermic direction) โ†’ less NHโ‚ƒ.
DECREASE temperature โ†’ shifts RIGHT (exothermic direction) โ†’ more NHโ‚ƒ.
THE HABER PROCESS โ€” compromise conditions:
High pressure (200 atm) โ†’ favours right (fewer moles of gas) โ†’ more NHโ‚ƒ.
Low temperature โ†’ favours right (exothermic) โ†’ more NHโ‚ƒ BUT reaction too slow.
Compromise temperature ~450ยฐC โ†’ fast enough rate, acceptable yield.
Iron catalyst โ†’ speeds up reaching equilibrium WITHOUT changing position.
This shows the trade-off in industrial chemistry: conditions that maximise yield often slow the rate, requiring a catalyst to compensate.
โš ๏ธ Common Mistake

A catalyst DOES NOT change the equilibrium position โ€” it only speeds up reaching equilibrium. Equilibrium position is determined by temperature only (not concentration or pressure โ€” those affect AMOUNTS but not the equilibrium constant). Temperature is the ONLY factor that changes the equilibrium constant itself.

๐Ÿ“ Key Equations
Nโ‚‚(g) + 3Hโ‚‚(g) โ‡Œ 2NHโ‚ƒ(g) ฮ”H = โˆ’92 kJ/mol (Haber process)
๐Ÿ“Œ Key Note

Le Chatelier: equilibrium shifts to OPPOSE any change. Increase reactant conc โ†’ shifts right. Increase pressure โ†’ shifts to fewer gas moles. Increase temperature โ†’ shifts in endothermic direction. Catalyst: faster equilibrium, same position. Haber: high P (more NHโ‚ƒ) + compromise T + Fe catalyst.

๐ŸŽฏ Matching Activity โ€” Le Chatelier's Principle Predictions

For Nโ‚‚ + 3Hโ‚‚ โ‡Œ 2NHโ‚ƒ (forward = exothermic), predict the effect of each change. โ€” drag the symbols on the right to match the component names on the left.

Equilibrium shifts right โ€” more NHโ‚ƒ
Drop here
Equilibrium shifts right โ€” more NHโ‚ƒ
Drop here
Equilibrium shifts left โ€” less NHโ‚ƒ
Drop here
No change in position
Drop here
Equilibrium shifts right โ€” more NHโ‚ƒ
Drop here
Increase temperature (forward is exothermic; reverse is endothermic โ€” heat drives reverse)
Remove NHโ‚ƒ as it forms โ€” system produces more to replace it
Increase concentration of Nโ‚‚ (more reactant added)
Add iron catalyst โ€” same equilibrium position, reached faster
Increase pressure (right has fewer moles: 2 vs 4)
๐ŸŽฏ Test Yourself
Question 1 of 2
1. For the reaction 2SOโ‚‚(g) + Oโ‚‚(g) โ‡Œ 2SOโ‚ƒ(g), increasing pressure shifts the equilibrium right. Why?
2. The Haber process uses 450ยฐC rather than a lower temperature. Why, given that lower temperature gives more ammonia?
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